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This document consists of 10 printed pages. IB17 05_1112_01/5RP © UCLES 2017 [Turn over Cambridge International Examinations Cambridge Secondary 1 Checkpoint MATHEMATICS 1112/01 Paper 1 April 2017 MARK SCHEME Maximum Mark: 50 IMPORTANT NOTICE Mark Schemes have been issued on the basis of one copy per Assistant examiner and two copies per Team Leader. Published This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of the examination. It shows the basis on which Markers were instructed to award marks. It does not indicate the details of the discussions that took place at an Markers’ meeting before marking began, which would have considered the acceptability of alternative answers. Mark schemes should be read in conjunction with the question paper and the Principal Examiner Report for Teachers. Cambridge will not enter into discussions about these mark schemes.

1112/01 Checkpoint Secondary 1 – Mark Scheme April 2017 Published Page 2 of 10 Mark scheme annotations and abbreviations M1 method mark A1 accuracy mark B1 independent mark FT follow through after error dep dependent oe or equivalent cao correct answer only isw ignore subsequent working soi seen or implied

1112/01 Checkpoint Secondary 1 – Mark Scheme April 2017 Published Page 3 of 10 Question Answer Marks Further Information 1(a) 63 (°) 1 1(b) 117 (°) 1 Follow through: 180 – answer to (a) 1(c) 63 (°) 1 Follow through: = answer to (a) or 180 – (b) Question Answer Marks Further Information 2 2t (or 2 × t or t × 2 or t + t) t – 10 (Oliver takes) half as long (as Mia) 3 Two correct answers. B2 One correct answer. B1 Only award if B2 not awarded. Question Answer Marks Further Information 3 2 One labeled arrow correctly placed. B1 Question Answer Marks Further Information 4 1 00.51A C D B 1.6 m 132 cm 1 m 20 cm 1.15 m1 m 6 cm 86 cm

1112/01 Checkpoint Secondary 1 – Mark Scheme April 2017 Published Page 4 of 10 Question Answer Marks Further Information 5(a) 5 and 3 1 Must be correct order. 5(b) 20 – 24 bar drawn to height 10 and 25 – 29 bar drawn to height 5 or their height for 25 – 29 1 The bars should have gaps between them. Follow through their 5 5(c) Ticks 'Yes' and gives a correct explanation e.g.  The modal interval was 15 – 19 on both days.  The tallest bar was 15 – 19 on Mondays and Tuesdays.  Both graphs peaked in the same place. 1 Do not accept an explanation that refers to just one graph, e.g. On Tuesdays the most common interval was 15 – 19 Question Answer Marks Further Information 6(a) 1 Accept any clear indication of the answer. 6(b) y = 7 or equivalent 1 6(c) 1 All correct for 1 mark. Accept any unambiguous indication of the answer.    Question Answer Marks Further Information 7 73 1 x + 5 = 0x = 5y = 5y = 5x

1112/01 Checkpoint Secondary 1 – Mark Scheme April 2017 Published Page 5 of 10 Question Answer Marks Further Information 8(a) 0.4 1 8(b) Any correct integers to make a fraction that lies between 52 and 2 1 (i.e. between 10040 and 10050 ) 1 e.g. 10045 , 209 , 73 , 10041 , 94 , ; 5 9 , 9 5 6 Question Answer Marks Further Information 9 21.676 1 Question Answer Marks Further Information 10(a) 11.316 1 10(b) 2.76 1 10(c) 113.16 1 Question Answer Marks Further Information 11 ($) 4.08 1

1112/01 Checkpoint Secondary 1 – Mark Scheme April 2017 Published Page 6 of 10 Question Answer Marks Further Information 12(a) 30 (minutes) 1 12(b) Safia and 12 1 12(c) The lines for Safia are steeper. 1 There must be a comment relating to steepness of the line or speed. Accept ‘her line is steeper’. Accept calculations or comparisons of speed. Question Answer Marks Further Information 13 x = 3 y = 2 2 x or y correct or 2  2  2  3  3  5 seen or implied by e.g. tree diagram, repeated division. B1 Question Answer Marks Further Information 14 6 5 4 3 2 1 0 5 4 3 2 1 0 1 4 3 2 1 0 1 2 3 2 1 0 1 23 2 1 0 1 234 1 0 1 234 5 1 2 3 4 5 6 1

1112/01 Checkpoint Secondary 1 – Mark Scheme April 2017 Published Page 7 of 10 Question Answer Marks Further Information 15(a) 250 1 Allow 2.5 × 10 2 15(b) 2.5 1 Allow 2.5 × 10 0 Question Answer Marks Further Information 16 ($)2.96 2 An answer containing the digits 296 but with an incorrectly positioned decimal point. or a complete correct method with at most one numerical error e.g. 1 8 5 × 1 6 1 0 1 0 1 8 5 0 2 8 6 0 M1 Question Answer Marks Further Information 17 ( –1, 3) 2 One correct coordinate or correct method for both coordinates or (3, –1) M1

1112/01 Checkpoint Secondary 1 – Mark Scheme April 2017 Published Page 8 of 10 Question Answer Marks Further Information 18 4 3 and 9 8 in correct order 2 Allow equivalent fractions. One correct fraction. B1 Question Answer Marks Further Information 19 2 3 coordinates are plotted in correct places or the image is the correct size and shape but incorrectly positioned. B1 2 4 6 8 10 2 46810 0 – 2 – 4 – 2 – 4 – 6 y x

1112/01 Checkpoint Secondary 1 – Mark Scheme April 2017 Published Page 9 of 10 Question Answer Marks Further Information 20 2 At least three correct. B1 Question Answer Marks Further Information 21 7 3 Complete correct method with at most one arithmetic or conversion error. M2 either for finding that one packet makes 3 litres of paint or for calculating that 20 litres of paint requires 4 kg of paint powder sight of 6 32 or 6.6… or 6 r4 B2 Only award if M2 not awarded. A correct conversion between g / kg or ml / l B1 Only award if neither M2 nor B2 awarded. 5 –1 0.125 5 –2 0.2 2 –3 0.25 3 –2 4% 2 2 1⎟ ⎠ ⎞ ⎜ ⎝ ⎛ 9 1

1112/01 Checkpoint Secondary 1 – Mark Scheme April 2017 Published Page 10 of 10 Question Answer Marks Further Information 22(a) (Reflection in the line) y = x 1 Do not accept just a line on the diagram. Combinations of transformations scores zero 22(b) 90° clockwise or 270° anticlockwise and (3,3) or 90° anticlockwise or 270° clockwise and (6,6) 2 Combinations of transformations scores zero. Either part correct B1 Question Answer Marks Further Information 23 1 Both answers needed. Question Answer Marks Further Information 24 × 1.2 0.25 4 4.8 1 1.2 1.44 0.3 2 Allow equivalent fractions. Two correct, allowing a follow through if ‘their 1.2’ × 1.2 is correctly evaluated in place of the 1.44 B1