[PDF] Cambridge Secondary Checkpoint - Math (1112) Specimen 2012 Paper 2 MS.pdf | Plain Text

This document consists of 5 printed pages and 1 blank page. © UCLES 2011 [Turn over UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS Cambridge Checkpoint MATHEMATICS 1112/02 Paper 2 For Examination from 2012 SPECIMEN MARK SCHEME 1 hour MAXIMUM MARK: 50

2 © UCLES 2011 1112/02/SM/12 Question 1 Part Mark Answer Further Information (a) 1 30 (b) 2 32 1 mark for their total ÷ 9 seen Total 3 Question 2 Part Mark Answer Further Information (a) (i) 1 9 (litres) (ii) 1 0.5 (litres) (b) 2 3 : 1 : 2 1 mark for 1500 : 500 : 1000 or better seen: Do not accept: 1.5 : 0.5 : 1 (c) 2 720 1 mark for 450 ÷ 5 or 90 seen Total 6 Question 3 Part Mark Answer Further Information (a) (i) 1 80 (ii) 2 5 1 mark for 100 = 35 + 15h or 75 seen (b) 2 32 + k [or equivalent] 1 mark for k + 2 = 3m seen or 32 − k or 3 2 + k as answer Total 5

3 © UCLES 2011 1112/02/SM/12 [Turn over Question 4 Part Mark Answer Further Information (a) (i) 1 15 18 (ii) 1 3.18 pm [or follow through answer from (a) (i)] Award mark for their time from (i) written in 12-hour clock. Must include pm (b) 1 19 (minutes) (c) 2 40 (km/h) 1 mark for 10 ÷ 0.25 [or equivalent] Total 5 Question 5 Part Mark Answer Further Information (a) 1 (3, 2) marked (b) 1 (–3, 3) (c) 1 C drawn correctly (d) 2 90° clockwise centre (0, 0) Or 270° anticlockwise. Answer must include both angle and direction. Total 5 Question 6 Part Mark Answer Further Information (a) 1 14, 17 both correct (b) 1 32 (c) 2 3p + 2 [or equivalent] 1 mark for expression with 3p (d) 1 Reason to show why 60 is not in the sequence e.g. Pattern 19 is 59 and pattern 20 is 62. None of the numbers are in the 3 times table and 60 is. 60 counters is pattern 19 1/3 Award 0 for answers such as: Pattern 60 uses 182 counters. It takes too long to draw. Total 5

4 © UCLES 2011 1112/02/SM/12 Question 7 Part Mark Answer Further Information (a) 1 15.6 (b) 2 4, 3 and 2 seen – 1 mark 24 (cm 3) – 1 mark any order, all correct (c) 2 39.(26990…) For 2 marks allow any rounding or truncating of 39.26990… 1 mark for 25 2 1 × ×π Total 5 Question 8 Part Mark Answer Further Information (a) 1 $1380 (b) 2 20 (%) 1 mark for 100 24048 × (c) 2 ($) 156 1 mark for 100 104 150× or 1004 150 150× + [or equivalent] or $6 seen Total 5 Question 9 Part Mark Answer Further Information 3 Arc radius 7 cm centre A – 1 mark Line 2 cm from AB – 1 mark Intersection labelled T – 1 mark Tolerance ± 2mm (Make and use overlay.) Total 3

5 © UCLES 2011 1112/02/SM/12 Question 10 Part Mark Answer Further Information (a) 1 All cells completed correctly. (b) (i) 1 251 or 0.04 or 4% Award marks in (b) and (c) if answers follow through correctly from answers given in table. (ii) 1 0 [Follow through answers given in table.] (c) 2 52 [Follow through answers given in table.] 1 mark for 25 10 or 0.4 or 40% Total 5 Question 11 Part Mark Answer Further Information 3 Correctly stating Pythagoras’ Theorem – 1 mark 40 2 + 25 2 = 1600 + 625 = 2225 – 1 mark 47.(16990…) – 1 mark Allow any rounding or truncation of the correct answer 47.16990… Total 3

6 © UCLES 2011 1112/02/SM/12 BLANK PAGE